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Let X be the number coming to a complete stop of
of 20 randomly chosen drivers. Then according to
the information given,
.(a)
Directly from the table on p. 719:
![\begin{displaymath}
P[ X \le 6 ] \; = \; .913.\end{displaymath}](img2.gif)
(b)
![\begin{displaymath}
P[ X = 6 ] \; = \; P[ X \le 6 ] - P[ X \le 5 ] \; = \;
.913 - .804 \; = \; .109 .\end{displaymath}](img3.gif)
(c)
![\begin{displaymath}
P[ X \ge 6 ] \; = \; 1 - P[ X \le 5 ] \; = \;
1 - .804 \; = \; .196 .\end{displaymath}](img4.gif)
(d)
![\begin{displaymath}
E[X] \; = \; 20 * .2 \; = \; 6 .\end{displaymath}](img5.gif)
Dennis Cox
2/19/2001